3+100x^2=39

Solution for 3+100x^2=39 equation:

3+100x^2=39

We move all terms to the left:

3+100x^2-(39)=0

We add all the numbers together, and all the variables

100x^2-36=0

a = 100; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·100·(-36)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*100}=\frac{-120}{200}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*100}=\frac{120}{200}
=3/5
$